Hello, In this blog we see the c program code to print multiplication table. In this program user give the input and depends on that integer number the multiplication table will displayed.

Code:

#include<stdio.h>
#include<conio.h>
void main()
{
 int s,i,a;
 clrscr();
    printf("Enter the number to print the multiplication table: ");
    scanf("%d",&s);
    printf("\n");
 for(i=1; i <= 10; i++)
 {
     printf("%d",s);
     printf(" * ");
     printf("%d",i);
     a=s*i;
     printf("=%d",a);
     printf("\n");
 }
getch();
}

         In the above code we use variable 's' to store the input value. And by using for loop the actual multiplication table is displayed.

Output:

Enter the number to print the multiplication table:7
7 * 1 = 7
7 * 2 = 14
7 * 3 = 21
7 * 4 = 28
7 * 5 = 35
7 * 6 = 42
7 * 7 = 49
7 * 8 = 56
7 * 9 = 63
7 * 10 = 70

char s[1000];

clrscr();

printf("Enter the string:");

gets(s);

while(s[c]!='\0')

            {

              if(s[c]=='a' || s[c]=='A' || s[c]=='e'|| s[c]=='E' || s[c]=='i' ||

              s[c]=='I' || s[c]=='o' || s[c]=='O' || s[c]=='u' || s[c]=='U')

            count++;

              c++;

            }

            printf("The no of vowels in the given string is:%d\n",count);

            getch();

}

______________________________________________

Output:

Enter the string: ccpptutoriallands_blogspot_com

The no of vowels in the given string is:8

Area of Rectangle

                          To calculate the area of the rectangle we must know the formula area of rectangle=Length*Breadth.

                              To perform this operation in the c language first take the three variables like length, breadth, and area to display or store the final answer. Then take the input from the user using scanf, then store that values in length and breadth as shown in the code. Pass these variables in formulae to calculate the area of the rectangle. Then the answer is stored in area variable, display area. Refer the following code to calculate the area of the rectangle.  

C language code to calculate area of Rectangle:

#include<stdio.h>

#include<conio.h>

void main()

{

   int length, breadth, area;

   clrscr();

   printf("\nEnter the Length of Rectangle:");

   scanf("%d",&length);           //to accept length of rectangle

   printf("\nEnter the Breadth of Rectangle:");

   scanf("%d",&breadth);        //to accept breadth of rectangle

   area=length*breadth;          //formula to find area of rectangle

   printf("\nArea of Rectangle:%d",area);//display area

   getch();

}

--------------------------------------------------------------------------------------

Output:

Enter the Length of Rectangle:6

Enter the Breadth of Rectangle:7

Area of Rectangle:42

                                          First, we see what Palindrome number. If we are giving input as 1254 the program separates each and every integer no and rearrange it in a reverse manner and again see the original number is the same or not, the i.e original number is 1254 and reversed number is 4521, but 1254 is not equal to 4521. Then the output is like 1254 is not a Palindrome number. To see the demo of this code see the following code. 

C language code to check the given number is a palindrome or not:

#include<stdio.h>

#include<conio.h>

void main()

{

    int n, a = 0, r, ori_no;

    clrscr();

    printf("Enter an integer: ");

    scanf("%d", &n);

    ori_no = n;//to store the original number

    while( n!=0 ) //number must be a non zero integer number

    {

       //following formulas to check the given number is palindrome or not

r = n%10;

a = a*10 + r;

n /= 10;

    }

    // palindrome if ori_no and r are equal

    if (ori_no == a)

printf("%d is a palindrome.", ori_no);

    else

printf("%d is not a palindrome.", ori_no);

    getch();

}

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output:

Enter an integer:546

546 is not a palindrome.

Enter an integer:45654

45654 is not a palindrome.